<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: tetration</title>
	<atom:link href="http://blog.yhuang.org/?feed=rss2&#038;p=1084" rel="self" type="application/rss+xml" />
	<link>https://blog.yhuang.org/?p=1084</link>
	<description>here.</description>
	<lastBuildDate>Tue, 14 Oct 2025 11:10:14 +0000</lastBuildDate>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>http://wordpress.org/?v=3.1.1</generator>
	<item>
		<title>By: Andrew</title>
		<link>https://blog.yhuang.org/?p=1084&#038;cpage=1#comment-113887</link>
		<dc:creator>Andrew</dc:creator>
		<pubDate>Wed, 26 Jun 2013 16:37:54 +0000</pubDate>
		<guid isPermaLink="false">http://allegro.mit.edu/~zong/wpress/?p=1084#comment-113887</guid>
		<description>This function is what I call the &quot;exponential commutator&quot; on the Tetration Forum. I think the fundamental problem with your proof is that you are dealing with inverse functions of functions that are not monotonic. When you try and find an inverse function of a nonmonotonic function, then you end up with a Riemann surface, which you might consider a multivalued function, and in order to think of it as a function, you must assign an index to each branch. Doing this, and going back to your proof, I would reword it as follows:

Let c = \sqrt{2}. Let f_0(x) be the branch of the inverse function of x^{1/x} that includes the point (x=sqrt(2), f_0=2). Let f_1(x) be the branch of the inverse function of x^{1/x} that includes the point (x=sqrt(2), f_1=4). Then f_0(c) = 2. Similarly, f_1(c) = 4. But then 2 = f_0(c) != f_1(c) = 4.

Your assumption that f_0 = f_1 is false, that is the where you went wrong.</description>
		<content:encoded><![CDATA[<p>This function is what I call the &#8220;exponential commutator&#8221; on the Tetration Forum. I think the fundamental problem with your proof is that you are dealing with inverse functions of functions that are not monotonic. When you try and find an inverse function of a nonmonotonic function, then you end up with a Riemann surface, which you might consider a multivalued function, and in order to think of it as a function, you must assign an index to each branch. Doing this, and going back to your proof, I would reword it as follows:</p>
<p>Let c = \sqrt{2}. Let f_0(x) be the branch of the inverse function of x^{1/x} that includes the point (x=sqrt(2), f_0=2). Let f_1(x) be the branch of the inverse function of x^{1/x} that includes the point (x=sqrt(2), f_1=4). Then f_0(c) = 2. Similarly, f_1(c) = 4. But then 2 = f_0(c) != f_1(c) = 4.</p>
<p>Your assumption that f_0 = f_1 is false, that is the where you went wrong.</p>
]]></content:encoded>
	</item>
</channel>
</rss>
