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	<title>Comments on: road path problem</title>
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	<link>https://blog.yhuang.org/?p=242</link>
	<description>here.</description>
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		<title>By: Hitchhiker</title>
		<link>https://blog.yhuang.org/?p=242&#038;cpage=1#comment-90374</link>
		<dc:creator>Hitchhiker</dc:creator>
		<pubDate>Tue, 22 Jun 2010 06:37:17 +0000</pubDate>
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		<description>Hopping onto a sphere with your question, where the elusive tangent planes abound, a lost poet is seeking the least bounding area he needs to cover to find that plane of Infinity. 

What would be the area of the towel draped over a sphere that would ensure that you find the tangent plane? 

Are there any tricks of reflection that simplifies stuff too?</description>
		<content:encoded><![CDATA[<p>Hopping onto a sphere with your question, where the elusive tangent planes abound, a lost poet is seeking the least bounding area he needs to cover to find that plane of Infinity. </p>
<p>What would be the area of the towel draped over a sphere that would ensure that you find the tangent plane? </p>
<p>Are there any tricks of reflection that simplifies stuff too?</p>
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		<title>By: me</title>
		<link>https://blog.yhuang.org/?p=242&#038;cpage=1#comment-89260</link>
		<dc:creator>me</dc:creator>
		<pubDate>Mon, 01 Mar 2010 21:20:02 +0000</pubDate>
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		<description>Very nice. That&#039;s a good way.</description>
		<content:encoded><![CDATA[<p>Very nice. That&#8217;s a good way.</p>
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		<title>By: Sam Hughes</title>
		<link>https://blog.yhuang.org/?p=242&#038;cpage=1#comment-89259</link>
		<dc:creator>Sam Hughes</dc:creator>
		<pubDate>Mon, 01 Mar 2010 09:29:12 +0000</pubDate>
		<guid isPermaLink="false">http://scripts.mit.edu/~zong/wpress/?p=242#comment-89259</guid>
		<description>Once you&#039;ve got the general shape of the curve, instead of making some trig expression and differentiating, just reflect the starting point across the line and draw a tangent line to the circle.  You get a nice 30-60-90 triangle.</description>
		<content:encoded><![CDATA[<p>Once you&#8217;ve got the general shape of the curve, instead of making some trig expression and differentiating, just reflect the starting point across the line and draw a tangent line to the circle.  You get a nice 30-60-90 triangle.</p>
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		<title>By: Anonymous</title>
		<link>https://blog.yhuang.org/?p=242&#038;cpage=1#comment-89241</link>
		<dc:creator>Anonymous</dc:creator>
		<pubDate>Sat, 20 Feb 2010 06:01:13 +0000</pubDate>
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		<description>@_@</description>
		<content:encoded><![CDATA[<p>@_@</p>
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