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	<title>Some stuff &#187; prediction</title>
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		<title>extrinsic bias in the prediction market</title>
		<link>https://blog.yhuang.org/?p=958</link>
		<comments>https://blog.yhuang.org/?p=958#comments</comments>
		<pubDate>Wed, 31 Oct 2012 05:55:54 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Uncategorized]]></category>
		<category><![CDATA[contract]]></category>
		<category><![CDATA[election]]></category>
		<category><![CDATA[math]]></category>
		<category><![CDATA[payoff]]></category>
		<category><![CDATA[prediction]]></category>
		<category><![CDATA[variance]]></category>

		<guid isPermaLink="false">http://scripts.mit.edu/~zong/wpress/?p=958</guid>
		<description><![CDATA[People have proposed using price signals from prediction markets to estimate the odds of certain events. On Intrade right now, you can buy contracts for the two outcomes of the 2012 US Presidential Election. Each contract expires at $10 if the event occurs or $0 if it doesn&#8217;t. For example, &#8220;Barack Obama wins&#8221; contracts are [...]]]></description>
			<content:encoded><![CDATA[<p>People have proposed using price signals from prediction markets to estimate the odds of certain events. On <a href="http://www.intrade.com/v4/misc/scoreboard/">Intrade right now</a>, you can buy contracts for the two outcomes of the 2012 US Presidential Election. Each contract expires at $10 if the event occurs or $0 if it doesn&#8217;t. For example, &#8220;Barack Obama wins&#8221; contracts are $6.33 a pop right now, while &#8220;Mitt Romney wins&#8221; contracts go for $3.65. On the page, these are taken directly as probabilities, because it is assumed that the gamble is zero-sum.</p>
<p>Specifically, if \(p\) and \(\bar{p}=1-p\) are respectively the probabilities of two complementary events, and \(a\) and \(b\) are respectively the prices of contracts on them, which can be bought and sold freely, then no-arbitrage imposes that \(-a-b+10 = 0\) and statistical no-arbitrage imposes \(-\bar{p}a +p(10-a) = 0\) and \(-pb +\bar{p}(10-b) = 0\). Solving indeed gives the prices \(a=10p\) and \(b=10\bar{p}\).</p>
<p>However, this isn&#8217;t the end of the story.<br />
<span id="more-958"></span><br />
The prediction market isn&#8217;t a closed system. Event outcomes are correlated with other payoffs outside of it. For instance, the election outcome has personal income tax consequences for certain individuals. While playing in the prediction market has no expected gain or loss, its contracts can diversify just such an external payoff to reduce its variance.</p>
<p>Suppose the total tax exposure of an Obama presidency is \(T_o\) and of a Romney presidency \(T_r\), and the probabilities of the two winning are respectively \(p\) and \(\bar{p}\), then the expected payoff is \(-pT_o -\bar{p}T_r\) while the variance is \(p\bar{p}(T_o-T_r)^2\).</p>
<p>Without loss of generality, assume \(T_o > T_r\). Then we can reduce the variance of the payoff by buying &#8220;Obama wins&#8221; contracts at normalized price \(q=a/10\). Let&#8217;s say we buy an amount worth \(N\) if expired in the money. The payoff becomes \(-T_o +(1-q)N\) with probability \(p\) and \(-T_r -qN\) with probability \(\bar{p}\). If the contracts are priced for no arbitrage as before (\(q=p\)), the expected payoff is \(-pT_o +p\bar{p}N -\bar{p}T_r -\bar{p}pN = -pT_o -\bar{p}T_r\) as before. However, the variance is \(p\bar{p}(T_o-T_r-N)^2\), which is a decrease for any \(N\in (0,2(T_o-T_r))\), with the aggregate (i.e. hedged) payoff becoming completely deterministic for \(N=T_o-T_r\). This is the point of maximal utility gain for a risk-averse hedger. One ends up &#8220;pre-paying&#8221; a portion of the potential additional tax burden in exchange for immunity from the election outcome.</p>
<p>The fact that hedgers exist and are biased in one direction means that the normalized price of a contract may no longer be exactly the probability of its expiring in the money. The imbalance in the market caused by risk aversion should create precisely an insurance premium to be added to the price of &#8220;Obama wins&#8221; contracts. Of course, the reality is more complicated, since not all individuals have homogeneous tax burdens under the outcomes. If the number of risk-averse hedgers is small, then the no-arbitrage assumption may still approximately hold.</p>
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		<item>
		<title>physicist trashtalking on economists</title>
		<link>https://blog.yhuang.org/?p=274</link>
		<comments>https://blog.yhuang.org/?p=274#comments</comments>
		<pubDate>Wed, 30 Jun 2010 13:06:23 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Uncategorized]]></category>
		<category><![CDATA[contrast]]></category>
		<category><![CDATA[decade]]></category>
		<category><![CDATA[econophysics]]></category>
		<category><![CDATA[guarantee success]]></category>
		<category><![CDATA[joseph l mccauley]]></category>
		<category><![CDATA[ltcm]]></category>
		<category><![CDATA[market]]></category>
		<category><![CDATA[physicist]]></category>
		<category><![CDATA[prediction]]></category>

		<guid isPermaLink="false">http://scripts.mit.edu/~zong/wpress/?p=274</guid>
		<description><![CDATA[&#8220;The physicist-run Prediction Company is an example of a company that has apparently extracted unusual profits from the market for over a decade. In contrast, economist-run companies like LTCM and Enron have gone belly-up. Being a physicist certainly doesn&#8217;t guarantee success &#8230; but if you are going to look for correlations in (market or any [...]]]></description>
			<content:encoded><![CDATA[<blockquote><p>&#8220;The physicist-run Prediction Company is an example of a company that has apparently extracted unusual profits from the market for over a decade. In contrast, economist-run companies like LTCM and Enron have gone belly-up. Being a physicist certainly doesn&#8217;t guarantee success &#8230; but if you are going to look for correlations in (market or any other) data then being a physicist might help.&#8221;</p>
<p>Joseph L. McCauley, writing in<br />
Dynamics of markets: econophysics and finance</p></blockquote>
]]></content:encoded>
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		<item>
		<title>earthquake prediction</title>
		<link>https://blog.yhuang.org/?p=233</link>
		<comments>https://blog.yhuang.org/?p=233#comments</comments>
		<pubDate>Fri, 15 Jan 2010 17:40:05 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Uncategorized]]></category>
		<category><![CDATA[analysis]]></category>
		<category><![CDATA[collection]]></category>
		<category><![CDATA[condition]]></category>
		<category><![CDATA[earthquake]]></category>
		<category><![CDATA[earthquake prediction]]></category>
		<category><![CDATA[foreshocks]]></category>
		<category><![CDATA[passive data]]></category>
		<category><![CDATA[prediction]]></category>
		<category><![CDATA[seismic data]]></category>
		<category><![CDATA[wave propagation]]></category>

		<guid isPermaLink="false">http://scripts.mit.edu/~zong/wpress/?p=233</guid>
		<description><![CDATA[Nowadays there is a large amount of geological and seismic data collected. When earthquakes occur people try to do data analysis on this data to see if there are predictors. For example, there are people who look for foreshocks or changes in wave propagation, and so on. It seems to me that the next step [...]]]></description>
			<content:encoded><![CDATA[<p>Nowadays there is a large amount of geological and seismic data collected. When earthquakes occur people try to do data analysis on this data to see if there are predictors. For example, there are people who look for foreshocks or changes in wave propagation, and so on. It seems to me that the next step beyond passive data collection would be to send active probe impulses to find the current condition of faults and whether they would fail soon. Is this done or not?</p>
<p>In any case, earthquake prediction may be a misnomer. One can never predict the precise time of an earthquake. But with more data and detection of ever smaller features, one can give more granular probabilistic predictions. So instead of saying there is a probability \(p\) of earthquake in the next 30 years, we may be able to either say (at any given moment) there is a probability \(p_1 \ll p\), or probability \(p_2 \gg p\) of one within the next year.</p>
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